Question:
What is the maximum amount of ammonia formed when 14 gm of N2 is mixed with 2 gm of H2.
Solution:
Reaction equation is:

N2 + 3H2 = 2NH3

The maximum amount of ammonia can be calculated according to chemical equation: n (NH3)=2 n(N2), n(NH3)=2/3n(H2) n (N2) = m(N2)/M(N2) = 14/28 = 0.5 mol n (H2) = m(H2)/M(H2) = 2/2 = 1 mol
3n (N2) = n (H2)
As there is lack of hydrogen, the amount of ammonia corresponds to the hydrogen amount in such way:
n (NH3)=2/3*n(H2) = 2/3 mol m (NH3) = n(NH3)*M(NH3) = 2/3*17 = 11.33 g
Answer: 11.33 g


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